6x^2-7x-98=0

Solution for 6x^2-7x-98=0 equation:

6x^2-7x-98=0

a = 6; b = -7; c = -98;
Δ = b2-4ac
Δ = -72-4·6·(-98)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-49}{2*6}=\frac{-42}{12}
=-3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+49}{2*6}=\frac{56}{12}
=4+2/3
$